1/(6x^2+9x)

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Solution for 1/(6x^2+9x) equation: 


D( x )

6*x^2+9*x = 0

6*x^2+9*x = 0

6*x^2+9*x = 0

6*x^2+9*x = 0

DELTA = 9^2-(0*4*6)

DELTA = 81

DELTA > 0

x = (81^(1/2)-9)/(2*6) or x = (-81^(1/2)-9)/(2*6)

x = 0 or x = -3/2

x in (-oo:-3/2) U (-3/2:0) U (0:+oo)

1/(6*x^2+9*x) = 0

6*x^2+9*x = 0

3*x*(2*x+3) = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

3*x*(x+3/2) = 0

1/(3*x*(x+3/2)) = 0

x belongs to the empty set

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